用Jersey构建RESTful服务1--HelloWorld

#一、环境

1.Eclipse Juno R2
2.Tomcat 7
3.Jersey 2.x(最新2.11版本测试通过) 下载地址（ https://jersey.java.net/download.html）

#二、流程

1.Eclipse 中创建一个 Dynamic Web Project ,本例为“RestDemo”
2.按个各人习惯建好包，本例为“com.waylau.rest.resources”
3.解压jaxrs-ri-2.7，将api、ext、lib文件夹下的jar包都放到项目的lib下；项目引入jar包
4.在resources包下建一个class“HelloResource”

	package com.waylau.rest.resources; 
	import javax.ws.rs.GET; 
	import javax.ws.rs.Path; 
	import javax.ws.rs.Produces; 
	import javax.ws.rs.PathParam; 
	import javax.ws.rs.core.MediaType; 
	@Path("/hello") 
	public class HelloResource { 
		@GET @Produces(MediaType.TEXT_PLAIN) 
		public String sayHello() 
		{ 
			return "Hello World!" ; 
		}
		
		@GET @Path("/{param}") 
		@Produces("text/plain;charset=UTF-8") 
		public String sayHelloToUTF8(@PathParam("param") String username) 
		{ 
			return "Hello " + username; 
		}
		
	}

5.修改web.xml,添加基于Servlet-的部署

<servlet> 
	<servlet-name>Way REST Service</servlet-name> <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class> 
	<init-param> 
	<param-name>jersey.config.server.provider.packages</param-name> 
	<param-value>com.waylau.rest.resources</param-value> </init-param> 
	<load-on-startup>1</load-on-startup> 
</servlet>

<servlet-mapping> 
	<servlet-name>Way REST Service</servlet-name> 
	<url-pattern>/rest/*</url-pattern> 
</servlet-mapping>

6.项目部署到tomcat,运行
7.浏览器输入要访问的uri地址 http://localhost:8089/RestDemo/rest/hello,输出Hello World!

http://localhost:8089/RestDemo/rest/hello/Way你好吗,输出Hello Way你好吗

参考：https://jersey.java.net/documentation/latest/user-guide.html

本章源码：https://github.com/waylau/RestDemo/tree/master/jersey-demo1-helloworld

Way Lau

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